b^2+5b+35=3b

Solution for b^2+5b+35=3b equation:

Simplifying
b2 + 5b + 35 = 3b

Reorder the terms:
35 + 5b + b2 = 3b

Solving
35 + 5b + b2 = 3b

Solving for variable 'b'.

Reorder the terms:
35 + 5b + -3b + b2 = 3b + -3b

Combine like terms: 5b + -3b = 2b
35 + 2b + b2 = 3b + -3b

Combine like terms: 3b + -3b = 0
35 + 2b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + 2b + -35 + b2 = 0 + -35

Reorder the terms:
35 + -35 + 2b + b2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + 2b + b2 = 0 + -35
2b + b2 = 0 + -35

Combine like terms: 0 + -35 = -35
2b + b2 = -35

The b term is 2b.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2b + 1 + b2 = -35 + 1

Reorder the terms:
1 + 2b + b2 = -35 + 1

Combine like terms: -35 + 1 = -34
1 + 2b + b2 = -34

Factor a perfect square on the left side:
(b + 1)(b + 1) = -34

Can't calculate square root of the right side.

The solution to this equation could not be determined.